Let n = 3 and (l1,l2,l3) = (5,10,3) Ordering I D(I) 1,2,3 5 + 5 + 10 + 5 + 10 + 3 = 38 1,3,2 5 + 5 + 3 + 5 + 3 + 10 = 31 2,1,3 10 + 10 + 5 + 10 + 5 + 3 = 43 2,3,1 10 + 10 + 3 + 10 + 3 + 5 = 41 3,1,2 3 + 3 + 5 + 3 + 5 + 10 = 29 3,2,1 3 + 3 + 10 + 3 + 10 + 5 = 34

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